CODEWITHSUNDEEP
scala
duckertito
duckertito

Reputation: 3635

Get list with unique sub-lists

I have a list of lists and I want to get the list with only unique sub-lists. For instance, this input:

List((123,List(List(xxx, abc),List(xxx,abc),List(yyy,abc))),
     (333,List(List(xxx, abc),List(yyy,abc),List(yyy,abc))))

should be converted into:

List((123,List(List(xxx,abc),List(yyy,abc))),
     (333,List(List(xxx, abc),List(yyy,abc))))

I tried this:

val unique = input.map(list => (list._1, list._2.distinct))

but it does not do the expected trick. What am I doing wrong?

Upvotes: 0

Views: 65

Answers (1)

Nagarjuna Pamu
Nagarjuna Pamu

Reputation: 14825

Just map and do distinct on the inner list.

mainList.map { case (a, list) => a -> list.distinct }

As your mainList consists of tuples, you can also use the tuple _2 to get the list in the tuple.

mainList.map(pair => pair._1 -> pair._2.distinct)

distinct will take care of keeping only the unique elements in the list.

Upvotes: 2

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