CODEWITHSUNDEEP
phpftp
sikas
sikas

Reputation: 5523

Getting the list of files over FTP

I want to print the list of files and only files from an FTP server, here is what I could accomplish.

<?php
    $ftp_server = "my ftp server";
    $conn_id = ftp_connect($ftp_server);
    $ftp_user_name = "ftp username";
    $ftp_user_pass = "ftp password";
    $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);
    $contents = ftp_nlist($conn_id, '/');
    for ($i = 0 ; $i < count($contents) ; $i++)
        echo "<li>" . substr($contents[$i],1) . "</li>";
    ftp_close($conn_id);
?>

but this prints the names of files and folders. How can I just print the names of files (files may not have extensions!)

Upvotes: 11

Views: 33195

Answers (5)

aesede
aesede

Reputation: 5703

If you are in the same server, you can do:

$contents = ftp_nlist($conn_id, '/');
// set the path to the folder
$path = '/home/user/public_html/my_folder/';
foreach ( $contents as $item ) {
    if ( is_file( $path . $item ) ) {
        echo $item . PHP_EOL;
    } else {
        continue;
    }
}

For remote server you can check if file exists with other methods.

Upvotes: 1

Lee Blake
Lee Blake

Reputation: 351

You could also use the ftp_mdtm() function. This always returns an error (-1) when it fails which would indicate a directory since this function doesn't work for directories. The one caveat is that it doesn't work on some systems (the manual doesn't state which ones), so you'd need to test if it worked first.

Upvotes: 2

Justin Ethier
Justin Ethier

Reputation: 134255

Here is a script that will do it for you, courtesy of a poster on ftp_nlist (PHP Docs):

<?php

//identify directories

function ftp_is_dir($dir) {
  global $ftp_connect;
  if (@ftp_chdir($ftp_connect, $dir)) {
       ftp_chdir($ftp_connect, '..');
       return true;
  } else {
       return false;
  }
}
$ftp_nlist = ftp_nlist($ftp_connect, ".");

//alphabetical sorting

sort($ftp_nlist);
foreach ($ftp_nlist as $v) {

//1. ftp_is_dir() is true => directory
  if (ftp_is_dir($v)) {

//output as [ directory ]
      echo "[ " . $v . " ]<br />\n";
  }
}
foreach ($ftp_nlist as $v) {

//2. ftp_is_dir() is false => file
  if (!ftp_is_dir($v)) {

//output as file
      echo "" . $v . "<br />\n";
  }
}
?>

Upvotes: 6

RobertPitt
RobertPitt

Reputation: 57268

if you use the ftp_rawlist like so:

$rawfiles = ftp_rawlist($conn, true); //true being for recursive

foreach ($rawfiles as $rawfile)
{
    $info = preg_split("/[\s]+/", $rawfile, 9);
    if($info[0]{0} == 'd')
    {
        //Directory
    }else
    {
        //File
        $size = byteconvert($info[4]);
        $chmod = chmodnum($info[0]);
        $date = strtotime($info[6] . ' ' . $info[5] . ' ' . $info[7]);
    }
}

Should get you closer to your goal.

Upvotes: 1

Jacob Mattison
Jacob Mattison

Reputation: 51072

Options:

1) you can use ftp_rawlist instead of ftp_nlist to get the full listing for the file/directory, which should indicate whether it's a directory. However, the format of that listing will depend on the operating system of the ftp server. For example, on a unix/linux system the raw listing might look something like this:

drwxrwxr-x  3 jm72 jm72  4096 Nov  2 16:39 myDir
-rw-rw-r--  1 jm72 jm72   257 Nov  2 16:39 myFile

where the "d" in the first column will tell you it's a directory. Not sure what it would look like on a Windows server.

2) for each file name you return, try to CD into it. If you can, it's a directory!

if (ftp_chdir($conn_id, substr($contents[$i],1)) {
  //it's a directory, don't include it in your list
  ftp_cdup($conn_id) //don't forget to go back up to the directory you started in!
}

Upvotes: 11

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