Reputation: 17617
I have a dataframe of shape (n, p)
and a series of length n
I can compare them with:
for i in df.keys():
df[i] > ts
Is there a way to do it in one line? something like df > ts
.
if yes, is it more efficient?
Upvotes: 4
Views: 5999
Reputation: 862671
I think you need DataFrame.gt
:
print (df.gt(s, axis=0))
Sample:
df = pd.DataFrame({'A':[1,2,3],
'B':[4,5,6],
'C':[7,8,9],
'D':[1,3,5],
'E':[5,3,6],
'F':[7,4,3]})
print (df)
A B C D E F
0 1 4 7 1 5 7
1 2 5 8 3 3 4
2 3 6 9 5 6 3
s = pd.Series([1,2,3])
print (s)
0 1
1 2
2 3
dtype: int64
print (df.gt(s, axis=0))
A B C D E F
0 False True True False True True
1 False True True True True True
2 False True True True True False
If need another functions for compare:
Upvotes: 7