CODEWITHSUNDEEP
phpc++
Buglinjo
Buglinjo

Reputation: 2077

Need to rewrite C++ code to PHP

I have a task. I need to rewrite C++ code to PHP. 

#include <iostream>
using namespace std;

struct Structure {
    int x;
};

void f(Structure st, Structure& r_st, int a[], int n) {
    st.x++;
    r_st.x++;
    a[0]++;
    n++;
}

int main(int argc, const char * argv[]) {

    Structure ss0 = {0};
    Structure ss1 = {1};
    int ia[] = {0};
    int m = 0;
    f(ss0, ss1, ia, m);
    cout << ss0.x << " "
         << ss1.x << " "
         << ia[0] << " "
         << m     << endl;

    return 0;
}

return of a compiler is 0 2 1 0. I have rewrote this code in PHP like this:

<?php

class Structure {
    public function __construct($x) {
        $this->x = $x;
    }

    public $x;
}

function f($st, $r_st, $a, $n) {
    $st->x++;
    $r_st->x++;
    $a[0]++;
    $n++;
}

$ss0 = new Structure(0);
$ss1 = new Structure(1);

$ia = [0];
$m = 0;

f($ss0, $ss1, $ia, $m);
echo $ss0->x    . " "
     . $ss1->x  . " "
     . $ia[0]   . " "
     . $m       . "\n";

return of this code is: 1 2 0 0. I know PHP and I know why it is returning this values. I need to understand how in C++ struct works and why a[0]++ is globally incremented. Please help to rewrite this code on PHP. I also know than there is no struct in PHP.

Upvotes: 1

Views: 133

Answers (3)

Starl1ght
Starl1ght

Reputation: 4493

Difference between:

function f($st, $r_st, $a, $n)
void f(Structure st, Structure& r_st, int a[], int n)

in C++ you always specify, pass by value or by reference, but in PHP there are some pre-defined rules.

Fix for 1st output

C++ part: st is passed by value, and original value, which you pass here is not changed. r_st is passed by reference, and original value is changed.

PHP part: both arguments are passed by reference, since they are classes.

Simple fix there is to clone object st and pass it to function to mimic C++ pass-by-copy, or clone it inside function.

Fix for 3rd output

in C++ int a[] is passed as pointer, so, original value is changed, but in PHP it is passed by value, and it is unchanged outside.

Simple fix for it would be &$a instead of $a in function parameters.

PS. I'm C++ developer, so, PHP part can be inaccurate in terminology.

Upvotes: 3

JustOnUnderMillions
JustOnUnderMillions

Reputation: 3795

Please help to rewrite this code on PHP.

Do it like this

function f($st, $r_st, &$a, $n) {

     $st= clone $st; #clone to get a real copy, not a refer

     $st->x++;
     $r_st->x++;
     $a[0]++; #&$a to simulate  ia[] (use as reference)
     $n++;
}

Read about references in PHP. I'm not a C++ dev.

http://php.net/manual/en/language.oop5.cloning.php

Upvotes: 0

Kevin Stich
Kevin Stich

Reputation: 783

The ss0 and ss1 variables you are passing in are by object accessors to that function. See Objects and references

The variables passed in are by value. See Passing by Reference

Upvotes: 1

Related Questions