Sr. André Baill
Sr. André Baill

Reputation: 105

Return array () in jQuery

I have the following HTML list

<table class="table table-bordered">
    <tbody>
        <tr>
            <th width="50" class="text-center">#</th>
            <th>Item do Pacote</th>
            <th>Valor</th>
            <th>Vencimento</th>
            <th width="50" class="text-center"></th>
        </tr>
        <tr>
            <td width="50" class="text-center">1</td>
            <td>Salgados - 100 Un</td>
            <td>R$ 150,00</td>
            <td width="200px">
            <input type="date" class="form-control" name="itens[0][data_vencimento]" id="itens[data_vencimento][]">            
            </td>
            <td width="50" class="text-center"><input type="checkbox" name="itens[0][item]" id="itens[item]" class="checados" value="150,00|1"></td>
        </tr>
                <tr>
            <td width="50" class="text-center">2</td>
            <td>Doces - 100 Un</td>
            <td>R$ 114,00</td>
            <td width="200px">
            <input type="date" class="form-control" name="itens[1][data_vencimento]" id="itens[data_vencimento][]">            
            </td>
            <td width="50" class="text-center"><input type="checkbox" name="itens[1][item]" id="itens[item]" class="checados" value="114,00|2"></td>
        </tr>
        <tr>
            <td width="50" class="text-center">3</td>
            <td>Refrigerante - 10 un</td>
            <td>R$ 85,00</td>
            <td width="200px">
            <input type="date" class="form-control array_teste" name="itens[2][data_vencimento]" id="itens[data_vencimento][]">            
            </td>
            <td width="50" class="text-center"><input type="checkbox" name="itens[2][item]" id="itens[item]" class="array_teste" value="85,00|3"></td>
        </tr>
    </tbody>
</table>

I need to retrieve all this data that is inside the fields, through a jQuery. I tried to do it this way:

$("#salvar_festa").click(function() {

    var itens = $(".array_teste").serializeArray();

    $.ajax({
        url: basePath + 'evento/salvar_festa',
        type: 'POST',
        dataType: 'html',
        data: {
            itens: itens
        },
    })
    .done(function(ret) {
        console.log("success");
        $('#mensagePage').html(ret);
    }); 

});

But in this way, I can not return the array objects, which should return as follows:

[item] => Array
    (
        [0] => Array
            (
                [data_vencimento] => 2016-12-05
                [itens] => 150,00|1
            )

        [1] => Array
            (
                [data_vencimento] => 2016-12-07
                [itens] => 114,00|2
            )

        [2] => Array
            (
                [data_vencimento] => 2016-12-22
                [itens] => 85,00|3
            )               
    )

But I have no idea how to resolve this issue. Within the save_fest in PHP, I then have print_r ($_POST);

My return via print_r ($_POST):

Array
(
    [itens] => Array
        (
            [0] => Array
                (
                    [name] => itens[0][data_vencimento]
                    [value] => 2016-12-01
                )

            [1] => Array
                (
                    [name] => itens[0][item]
                    [value] => 150,00|1
                )

            [2] => Array
                (
                    [name] => itens[1][data_vencimento]
                    [value] => 2016-12-01
                )

            [3] => Array
                (
                    [name] => itens[1][item]
                    [value] => 114,00|2
                )

            [4] => Array
                (
                    [name] => itens[2][data_vencimento]
                    [value] => 2016-12-01
                )

            [5] => Array
                (
                    [name] => itens[2][item]
                    [value] => 85,00|3
                )

        )

)

Upvotes: 1

Views: 41

Answers (1)

Atmahadli
Atmahadli

Reputation: 687

you could use .serialize() http://jqapi.com/#p=serialize

not .serializeArray() http://jqapi.com/#p=serializeArray

the difference is: if you use .serializeArray() you need to iterate through them to get the correct value and this function is usually for debugging only (unless you really need it for some reason)

Upvotes: 1

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