Converting int to char

Question

Task is to get int using scanf("%d") then print it again using printf("%с") without standard functions like atoi , itoa .As i understood i need to divide all numbers then add \0 char and print it, however how can i divide it. I thought about loop for dividing number%10 + /0 and number/10 to decrease number for 1 character . Therefore code should look smoothing like this

#include <conio.h>
#include <stdio.h>

main(void)
{
int number,reserve ;
char Array[50];
scanf_s("%d",&number);
if (number > 0 || number == 0)
{
    do
    {
        reserve = number % 10;
        printf("%c", reserve + '/0');
        number /= 10;
    } while (number != 0);
}
else
{
    number *= -1;
    printf("-");
    do
    {
        reserve = number % 10;
        printf("%c", reserve + '/0');
        number /= 10;
    } while (number != 0);

}
_getch();
return 0;

}

As well there can be negative number so i need some if statement to check if it is negative and in case it is loop should avoid it it so we won't get smthing like -%10

So i don't know if loop is correct (hope someone will fix it and explain me how it is supposed to be). Waiting for your advices.

Answer 1

this will help you, adopt for your purposes

#include <stdio.h>

int main() {

    int a;
    int i = 0;
    int str_size = 0;   
    char str[11] = {};
    char tmp;

    scanf("%d", &a);

    while (a) {
        str[str_size++] = a % 10 + '0';
        a /= 10;
    }

    str_size--;

    while (i < str_size) { // rewind 
        tmp = str[i];
        str[i++] = str[str_size];
        str[str_size--] = tmp;
    }
    printf("%s", str);

    return 0;
}

Answer 2

One side effect of the line

number = number % 10;

is that you lose the original value of number. So when you go to do

number = number/10;

it would always get the value zero. To fix this, store the original value somewhere else, or use another variable to do your character conversion (modulo 10, then plus \0).

Also, your loop needs to be re-examined. This process of modulo, add \0, divide, repeat, should stop when the result of the division is zero (i.e. there are no more digits to print). Another thing to think about is: in what order are these digits being printed?

I'll leave it to you to to figure out how to determine if the value of an int is greater than or less than zero, since you didn't attempt that in this snippet.