CODEWITHSUNDEEP
pythonstring
Tank
Tank

Reputation: 521

More efficient way of joining a tuple?

Is there a more efficient way of joining a tuple? since my rx gives me a tuple? Moreover c is '7:30' ' AM' at the end, and i need '7:30 AM'

import re

rx = r"(?i)\b(\d{1,2}:\d{2})(?:-\d{1,2}:\d{2})?(\s*[pa]m)\b"
s = "ankkjdf 7:30-8:30 AM dds "

matches = re.findall(rx, s)

m=str(matches)

a =''.join(m[2:8])
b= ''.join(m[9:15])

c = "".join(a + b)

print(c)

Upvotes: 2

Views: 70

Answers (1)

Copperfield
Copperfield

Reputation: 8510

>>> import re
>>> rx = r"(?i)\b(\d{1,2}:\d{2})(?:-\d{1,2}:\d{2})?(\s*[pa]m)\b"
>>> s = "ankkjdf 7:30-8:30 AM dds "
>>> matches = re.findall(rx, s)
>>> matches
[('7:30', ' AM')]
>>> [ "".join(x) for x in matches]
['7:30 AM']
>>>

or 

>>> "".join(matches[0])
'7:30 AM'
>>>

or directly from the source

>>> [ "".join(x) for x in re.findall(rx, s)]
['7:30 AM']
>>> "".join( re.findall(rx, s)[0] )
'7:30 AM'
>>>

there is no reason to do m=str(matches), just fuse together what you get in whatever way you want...

with the latest example

>>> test="Join us for a guided tour of the Campus given by Admissions staff. The tour will take place from 1:15-2:00 PM EST and leaves from the Admissions Office."
>>> [ "".join(x) for x in re.findall(rx, test)]
['1:15 PM']
>>> "".join( re.findall(rx, test)[0] )
'1:15 PM'
>>>

Upvotes: 2

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