CODEWITHSUNDEEP
javascriptjavascript-objects
PlayHardGoPro
PlayHardGoPro

Reputation: 2923

How to populate associative array through for loop

I need to create this kind of element inside my array: 

{ Field1: "2011/04/23", Field2: 8, Field3: "Adam", Field4: "Den"},  
{ Field1: "2011/03/25", Field2: 6, Field3: "Honey",Field4: "Singh"}

How may I increasce that field1 counter ? 

var resultado = [];
    for(i=0;  i< dados.length; i++){                
        resultado[i] = { "Field"+i: dados[columns[i]]};
    }

If I try to do like above, it gives me an error saying I can't use the + character. How may I achieve my goal ?

Obs: i'll not always have 4 fields, it may vary.

UPDATE

Following the answers I could achieve part of what I need, now the code is like this: 

var resultado = [];
    for(i=0;  i< dados.length; i++){                
        resultado[i] = { ["Field"+i]: dados[columns[i]]};
    }

But I'm not managing to write all of that in a single position of the array.
How may I get this: 

var results = [
      {
       Field1: "2011/04/23",
       Field2: 8,
       Field3: "Adam",
       Field4: "Den"  
      }, //First Element  

      {
       Field1: "2011/03/25",
       Field2: 6,
       Field3: "Honey",
       Field4: "Singh"  
      } //Second Element
    ];

I'm using JqueryDataTable, so I need to create an obj to populate it dinamically.

I have an ajax that returns me a Json with the name of the columns. 

["id_localidade","cod_munic","id_bairro","id_endereco"]  
//These are column names that I need to use later.

Then I have another Ajax to bring me the DATA from this same table as a Json: 

[  
{"id_bairro":"1","dsc_bairro":"PONTE DOS CARVALHOS"},  
{"id_bairro":"2","dsc_bairro":"CHARNECA"},  
{"id_bairro":"3","dsc_bairro":"SAO FRANCISCO"},  
{"id_bairro":"4","dsc_bairro":"ROSARIO"}  
]

So now I need to use these two arrays and create the this: 

{ Field1: "2011/04/23", Field2: 8, Field3: "Adam", Field4: "Den"},

Where Field1, Field2, FieldN will depend on how many columns the selected column has. (As I have the name of those columns I just need to count it).

What I tried so far (without success): 

var nFields   = Object.keys(dados[0]).length;//Number of columns
var nElements = dados.length; //Number of registers

var resultado = [];
for(i=1;  i<= nElements; i++){
   for(j=0; j < nFields; j++){
      var temp = [];
      temp.push({ ["Field"+ (j+1)]: dados[j][ columns[j]['sTitle'] ] });
      resultado = temp;
   }                
}

Upvotes: 1

Views: 532

Answers (4)

guest271314
guest271314

Reputation: 1

You can use brackets to produce a computed name for a property of an object.

Obs: i'll not always have 4 fields, it may vary.

If dados array is an array of arrays, utilize nested for loop to iterate each element of current dados[i] array.

var dados = [
  [0, 1, 2],
  [3, 4],
  [5, 6, 7, 8]
];
var resultado = [];
var prop = "Field";
for (var i = 0; i < dados.length; i++) {
  resultado[i] = {};
  for (var n = 1; n < dados[i].length; n++) {
    resultado[i][prop + n] = dados[i][n - 1];
  }
}

console.log(resultado);

Upvotes: 1

Nina Scholz
Nina Scholz

Reputation: 386560

You could use a default object, if resultado[i] is not set and use bracket notation for the access.

resultado[i] = resultado[i] || {};
resultado[i]["Field" + i] = dados[columns[i]];

Upvotes: 1

Dekel
Dekel

Reputation: 62536

Just as a note - in javascript they are not called associative arrays, they are just objects.

option1:

You can create an empty object, and then add the key using obj[key]:

var resultado = [];
for(i=0;  i< dados.length; i++){                
    resultado[i] = {};
    resultado[i]["Field"+i] = dados[columns[i]]
}

option2:

You can create the name of the key before using it:

var resultado = [];
for(i=0;  i< dados.length; i++){                
    key = "Field"+i
    resultado[i] = {key: dados[columns[i]]};
}

Upvotes: 1

mitch
mitch

Reputation: 2245

Just use push method.

var resultado = [];
for(var i=0;  i< dados.length; i++){                
    resultado.push({ "Field"+i : dados[columns[i]]});
}

Upvotes: 0

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