CODEWITHSUNDEEP
pythonsqlsqlite
Pwnna
Pwnna

Reputation: 9538

Python SQLite3 Problem with?

Im currently learning SQLite3 with Python. I'm looking at the manual, and it tells me to do something like the following:

data = (tablename, )
c.execute("CREATE TABLE IF NOT EXISTS ?(uid INTEGER PRIMARY KEY, title TEXT NOT NULL, duedate INTEGER NOT NULL, description TEXT, archived INTEGER)", data)

I'm getting an error, however. It's stated as follows:

sqlite3.OperationalError: near "?": syntax error

What's going on?

Upvotes: 1

Views: 471

Answers (1)

mouad
mouad

Reputation: 70059

sadly the DB-API’s parameter substitution ? don't work with table name , columns name .. and it's the same in all DB API in python.

the DB-API’s parameter substitution just work for value like in SELECT * FROM table WHERE id = ?, so you will have to do string formating or just put the name table in the string directly.

query = "CREATE TABLE IF NOT EXISTS %s (uid INTEGER PRIMARY KEY, title TEXT NOT NULL, duedate INTEGER NOT NULL, description TEXT, archived INTEGER)" % table_name

conn.execute(query)

Upvotes: 3

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