CODEWITHSUNDEEP
python
user3508811
user3508811

Reputation: 925

how to create a regex to remove multiple characters?

I am trying to figure out a way to create a single expression that will work for both branch1 and branch2 below?I need to remove the words -dev and -rel from branch,how can I do that?

chars_to_remove = ['-dev','-rel']
branch1 = 'bt.lnx.2.1-dev'
branch2 = 'bt.lnx.2.1-rel'
component = branch1.translate(None, ''.join(chars_to_remove))//should work for both branch1 & branch2
print component

EXPECTED OUTPUT:(for both branch1 and branch2)-

bt.lnx.2.1

Upvotes: 0

Views: 398

Answers (4)

Ahasanul Haque
Ahasanul Haque

Reputation: 11134

import re

chars_to_remove = ['({}.*)'.format(i) for i in chars_to_remove] 

def trimmer(your_string):
    return re.sub(r'|'.join(chars_to_remove),'',your_string)

print trimmer(branch1)
print trimmer(branch2)

Output:

'bt.lnx.2.1'
'bt.lnx.2.1'

Upvotes: 0

Skycc
Skycc

Reputation: 3555

use regex, it remove chars_to_remove at end of string, remove the $ from the regex if you wanna remove all the match including match at middle also

import re
chars_to_remove = ['-dev','-rel'] # modify char to remove here
def remove_char(s):
    return re.sub("({})$".format('|'.join(chars_to_remove)), '',  s)

branch1 = 'bt.lnx.2.1-dev'
branch2 = 'bt.lnx.2.1-rel'
remove_char(branch1) # 'bt.lnx.2.1'
remove_char(branch2) # 'bt.lnx.2.1'

Upvotes: 0

Suman
Suman

Reputation: 55

Try this:

print (branch1.replace('-dev','').replace('-rel',''))

print (branch2.replace('-dev','').replace('-rel',''))

Upvotes: 3

Khyber Thrall
Khyber Thrall

Reputation: 51

If they're always at the end you can simply use string slicing.

if branch[-4:] == '-dev' or branch[-4:] == '-rel':
     branch = branch[:-4]

If they're not all at the end, you might want to use the re module.

Upvotes: -1

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