CODEWITHSUNDEEP
javaloopsnested-loops
Ridha Anshari
Ridha Anshari

Reputation: 23

Nested loop based on user input in Java

Is it possible to make nested loop based on user input in Java? For example, if the user inputs 3, then there are 3 loops that are nested (3 levels of loop). If it's possible, could you show me how?

I needed it to generate every possibilities of something. Every loop happens twice. So there are 2^n possibilities.

Thanks for the big help.

EDIT I haven't coded the looping calculation part yet because I'm still trying to figure out the algorithm. Kriteria.java

public class Kriteria {

    String name;
    int min, max;
    double lowMembership, highMembership;
public Kriteria(String name, int min, int max,low,high) {
        this.name = name;
        this.min = min;
        this.max = max;
        this.lowMembership = low;
        this.highMembership = high;
    }

}

MainClass.java

public class MainClass {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
    ArrayList<Kriteria> listKriteria = new ArrayList();

//later on the user can decide how many kriteria he wanted and create them            
    Kriteria kriteria1,kriteria2,kriteria3;

    kriteria1 = new Kriteria("Kriteria 1", 1, 10, 4,3,5);
    listKriteria.add(kriteria1);
    kriteria2= new Kriteria2("Kriteria 2", 5, 20, 13,7,18);
    listKriteria.add(kriteria2);
    kriteria3 = new Kriteria3("Kriteria 3", 3, 8, 5,4,7);
    listKriteria.add(kriteria3);

/* I want something like this:

1st 
double result= Kriteria1.lowMembership + Kriteria2.lowMembership + Kriteria3.lowMembership;
2nd
double result= Kriteria1.lowMembership + Kriteria2.lowMembership + Kriteria3.highMembership;
3rd
double result= Kriteria1.lowMembership + Kriteria2.highMembership + Kriteria3.highMembership;
and so on for each possibility...
*/

   }        
}

is it enough? I changed the naming and mechanism a bit to make it shorter

Upvotes: 0

Views: 1222

Answers (1)

Nikesh Joshi
Nikesh Joshi

Reputation: 825

You can't generate code at runtime, for this kind of problem simply go for recursion.

void fun(int n)
{
     if(n==0)
         return;
     System.out.println(n);
     fun(n-1);
}

Upvotes: 1

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