CODEWITHSUNDEEP
c#linqdynamicreflectionfilter
Foyzul Karim
Foyzul Karim

Reputation: 4492

C# LINQ select property if it has a custom attribute

I have a list of StudentViewModel object. I am binding this list with a DataGridView, and the column generatation is set to automatic according to the bound model's properties. 

   public async Task LoadGridView()
    {
        Tuple<List<StudentViewModel>, int> result = await App.StudentService.SearchAsync(studentRequestModel);
        dataGridView1.DataSource = null;
        dataGridView1.DataSource = result.Item1;
    }

In the StudentViewModel, I have decorated some of the properties with a custom attribute IsViewable.

[AttributeUsage(AttributeTargets.Property)]
public class IsViewable: Attribute
{
    public bool Value { get; set; }
}

usage: 

        [IsViewable(Value = true)]
        public string Name { get; set; }

Idea is, just before binding with the UI Control, I want to filter the list and make a new list of anonymous object so that my grid will be populated with only selected properties.

enter image description here

Note: I don't want to create separate view models specific to Grids. I will refactor it if it creates performance issues.

Upvotes: 1

Views: 3143

Answers (1)

Foyzul Karim
Foyzul Karim

Reputation: 4492

The catch is, I serialized the dynamic list and then deserialized. Then I bind that dynamic list with the datagridview and it worked like a charm.

enter image description here

The whole project can be found here foyzulkarim/GenericComponents

Caller / Usage: 

        Type type = typeof(StudentViewModel);
        PropertyInfo[] properties = type.GetProperties();
        var infos = properties.Where(x => x.CustomAttributes.Any(y => y.AttributeType == typeof(IsViewable))).ToList();
        List<StudentViewModel> models = result.Item1;
        List<dynamic> list = models.Select(x => GetValue(x, infos)).ToList();
        string serializeObject = JsonConvert.SerializeObject(list);
        var deserializeObject = JsonConvert.DeserializeObject<List<dynamic>>(serializeObject);
        dataGridView1.DataSource = deserializeObject;

enter image description here

enter image description here

Upvotes: 1

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