CODEWITHSUNDEEP
pythonstringtuples
norpa
norpa

Reputation: 127

Getting second element of a tuple (in a list of tuples) as a string

I have an output that is a list of tuples. It looks like this:

annot1=[(402L, u"[It's very seldom that you're blessed to find your equal]"), 
        (415L, u'[He very seldom has them in this show or his movies]')…

I need to use the second part of the tuple only to apply ‘split’ and get each word on the sentence separately.

At this point, I’m not able to isolate the second part of the tuple (the text).

This is my code:

def scope_match(annot1):
    scope = annot1[1:]
    scope_string = ‘’.join(scope)
    scope_set = set(scope_string.split(' '))

But I get:

TypeError: sequence item 0: expected string, tuple found

I tried to use annot1[1] but it gives me the second index of the text instead of the second element of the tuple.

Upvotes: 1

Views: 6014

Answers (2)

Mohammad Yusuf
Mohammad Yusuf

Reputation: 17054

You can do something like this with list comprehensions:

annot1=[(402L, u"[It's very seldom that you're blessed to find your equal]"), 
        (415L, u'[He very seldom has them in this show or his movies]')]
print [a[1].strip('[]').encode('utf-8').split() for a in annot1]

Output:

[["It's", 'very', 'seldom', 'that', "you're", 'blessed', 'to', 'find', 'your', 'equal'], ['He', 'very', 'seldom', 'has', 'them', 'in', 'this', 'show', 'or', 'his', 'movies']]

You can calculate the intersection of strings in corresponding positions in annot1 and annot2 like this:

for x,y in zip(annot1,annot2):
    print set(x[1].strip('[]').encode('utf-8').split()).intersection(y[1].strip('[]').encode('utf-8').split())

Upvotes: 4

Iluvatar
Iluvatar

Reputation: 1537

annot1 is a list of tuples. To get the string from each of the elements, you can do something like this

def scope_match(annot1):
    for pair in annot1:
        string = pair[1]
        print string  # or whatever you want to do

Upvotes: 1

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