CODEWITHSUNDEEP
pythonlistmultiplication
user7416
user7416

Reputation: 145

Multiplication of lists of different sizes

import numpy as np

newResidues = [1, 2, 3, 4, 5]
newI = [[1,0,1,0,1],[1,1,0,0,0],[1,0,0,1,0]]
sqrt = 10

templist = []

from itertools import compress

for i in newI:
   valuesofresidues = list(compress(newResidues, i))
   templist = valuesofresidues
   print templist

This returns 

[1, 3, 5]
[1, 2]
[1, 4]

Now, let's take the first row, [1,3,5] I need to do the following operations pow((sqrt + 1),2) + pow((sqrt + 3), 2) + pow((sqrt + 5),2) and return the sum for all rows separately. So that it returns

515
265
317

I tried adding a nested for loop 

for temp in range(n):
    x = templist[temp]
    xsquare = pow(sqrt+x,2)

but it's not working the way I need it to. Any help will be appreciated, thanks!

Upvotes: 0

Views: 59

Answers (1)

rassar
rassar

Reputation: 5660

Use this function to get the sum:

def getSum(sublist):
    return sum(pow(sqrt+x, 2) for x in sublist)

Shell example:

>>> for i in newI:
   valuesofresidues = list(compress(newResidues, i))
   templist = valuesofresidues
   getSum(templist)


515.0
265.0
317.0

Upvotes: 2

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