CODEWITHSUNDEEP
pythondictionary
Oleg
Oleg

Reputation: 847

Python dict ordering by inner dict value

all.

I need help with dictionary ordering issue.

I have dictionary that I want sort by inner dictionary value. In my case I need sort dictionary by 'ordering' value

{'MotoType': {'verbos_name': 'Тип', 'ordering': 6, 'filtering': False, 'value': 'Кросс'}, 'MarkaMoto': {'verbos_name': 'Марка', 'ordering': 1, 'filtering': True, 'value': 'Honda'}, 'Condition': {'verbos_name': 'Состояние', 'ordering': 5, 'filtering': False, 'value': 'Среднее'}, 'Color': {'verbos_name': 'Цвет', 'ordering': 99, 'filtering': False, 'value': 'Красный'}, 'probeg': {'verbos_name': 'Пробег км.', 'ordering': 6, 'filtering': False, 'value': '34500'}, 'CreatYear': {'verbos_name': 'Год выпуска', 'ordering': 6, 'filtering': True, 'value': '2010'}, 'ModelMoto': {'verbos_name': 'Модель', 'ordering': 2, 'filtering': True, 'value': 'VFR800FI'}}

Upvotes: 0

Views: 71

Answers (2)

Fujiao Liu
Fujiao Liu

Reputation: 2253

sorted the data and use OrderedDict keeps the order.

>>> a ={'MotoType': {'verbos_name': 'Тип', 'ordering': 6, 'filtering': False, 'value': 'Кросс'}, 'MarkaMoto': {'verbos_name': 'Марка', 'ordering': 1, 'filtering': True, 'value': 'Honda'}, 'Condition': {'verbos_name': 'Состояние', 'ordering': 5, 'filtering': False, 'value': 'Среднее'}, 'Color': {'verbos_name': 'Цвет', 'ordering': 99, 'filtering': False, 'value': 'Красный'}, 'probeg': {'verbos_name': 'Пробег км.', 'ordering': 6, 'filtering': False, 'value': '34500'}, 'CreatYear': {'verbos_name': 'Год выпуска', 'ordering': 6, 'filtering': True, 'value': '2010'}, 'ModelMoto': {'verbos_name': 'Модель', 'ordering': 2, 'filtering': True, 'value': 'VFR800FI'}}
>>> from collections import OrderedDict
>>> OrderedDict(sorted(a.items(), key=lambda t:t[1]['ordering']))
OrderedDict([('MarkaMoto', {'value': 'Honda', 'filtering': True, 'verbos_name': 'Марка', 'ordering': 1}), ('ModelMoto', {'value': 'VFR800FI', 'filtering': True, 'verbos_name': 'Модель', 'ordering': 2}), ('Condition', {'value': 'Среднее', 'filtering': False, 'verbos_name': 'Состояние', 'ordering': 5}), ('probeg', {'value': '34500', 'filtering': False, 'verbos_name': 'Пробег км.', 'ordering': 6}), ('MotoType', {'value': 'Кросс', 'filtering': False, 'verbos_name': 'Тип', 'ordering': 6}), ('CreatYear', {'value': '2010', 'filtering': True, 'verbos_name': 'Год выпуска', 'ordering': 6}), ('Color', {'value': 'Красный', 'filtering': False, 'verbos_name': 'Цвет', 'ordering': 99})])
>>>

Upvotes: 2

Drathier
Drathier

Reputation: 14539

Dictionaries are unordered in Python. You can use OrderedDict, which preserves ordering.

from collections import OrderedDict

a = OrderedDict({'MotoType': {'verbos_name': 'Тип', 'ordering': 6, 'filtering': False, 'value': 'Кросс'},
     'MarkaMoto': {'verbos_name': 'Марка', 'ordering': 1, 'filtering': True, 'value': 'Honda'},
     'Condition': {'verbos_name': 'Состояние', 'ordering': 5, 'filtering': False, 'value': 'Среднее'},
     'Color': {'verbos_name': 'Цвет', 'ordering': 99, 'filtering': False, 'value': 'Красный'},
     'probeg': {'verbos_name': 'Пробег км.', 'ordering': 6, 'filtering': False, 'value': '34500'},
     'CreatYear': {'verbos_name': 'Год выпуска', 'ordering': 6, 'filtering': True, 'value': '2010'},
     'ModelMoto': {'verbos_name': 'Модель', 'ordering': 2, 'filtering': True, 'value': 'VFR800FI'}})

out = sorted(a.items(), key=lambda i: i[1]["value"])

print(out)

which outputs

[('CreatYear', {'value': '2010', 'filtering': True, 'ordering': 6, 'verbos_name': 'Год выпуска'}), ('probeg', {'value': '34500', 'filtering': False, 'ordering': 6, 'verbos_name': 'Пробег км.'}), ('MarkaMoto', {'value': 'Honda', 'filtering': True, 'ordering': 1, 'verbos_name': 'Марка'}), ('ModelMoto', {'value': 'VFR800FI', 'filtering': True, 'ordering': 2, 'verbos_name': 'Модель'}), ('Color', {'value': 'Красный', 'filtering': False, 'ordering': 99, 'verbos_name': 'Цвет'}), ('MotoType', {'value': 'Кросс', 'filtering': False, 'ordering': 6, 'verbos_name': 'Тип'}), ('Condition', {'value': 'Среднее', 'filtering': False, 'ordering': 5, 'verbos_name': 'Состояние'})]

Upvotes: 2

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