CODEWITHSUNDEEP
javaregex
pehr.ans
pehr.ans

Reputation: 109

regular expression matching url

I would like to match the fragment portion of a url, meaning a sub-string that begins with '#'.

A URL should not have a fragment and a query. So, if a '?' precedes the first '#', the sub-string "#..." should not match.

example of url(s) with fragment:

http://exampleurl.com:8080/#this?whole#thing?is#a?fragment

http://exampleurl.com:8080#this?whole#thing?is#a?fragment

http://exampleurl.com#this?whole#thing?is#a?fragment

example of url with no fragment:

http://exampleurl.com:8080/?#this?whole#thing?is#NOT?a#fragment

http://exampleurl.com:8080/?this?whole#thing?is#NOT?a#fragment

The regular expression should match "#this?whole#thing?is#a?fragment" in the first example, but should not match anything in the second example. As stated before, if there is a '?' preceding the first '#', then it will be considered a query and not a fragment.

attempt: 

"#+.+$"

The above regex matches correctly in regards to the first example, but it will also match the sub-string "#thing?is#NOT?a#fragment" in the second example which is not desirable. I am not sure how to put in the proper guards to prevent it from matching with a sub-string that has a '?' preceding it.

Thanks!

Upvotes: 1

Views: 151

Answers (1)

gaspo
gaspo

Reputation: 72

This one matched all your cases correctly. Result is in first group. 

/^[^#?]*(#.*)/gm

check results here https://regex101.com/r/p6tsh2/1

Upvotes: 2

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