CODEWITHSUNDEEP
java
ccs
ccs

Reputation: 151

how to validate no duplicated int type data in java

I wanted to check whether the txt file contain duplicate data or not when i click the button load Data.

For example ID, ID in an int.
0001
0002
0003

here is the partial code

while (scnr.hasNextInt()) 
{
   id  = scnr.nextInt();

   int checkid = id;
   if(checkid == id) {
        System.out.println("invalid id");
   } else{
        clients.put(new Integer(id), new Client(id));
   }
}

This code doesn't work.
And also, i had tried this method but it is not working too.

    if(checkid.matches(id))
    {
        System.out.println("invalid id");
    }

Cannot invoke matches (int) on the primitive type int

i not understand why String type data can use .matches() but int cannot.
what method i can implant to validate the int type data????

Upvotes: 0

Views: 1116

Answers (3)

Tony
Tony

Reputation: 6158

First, you should understand int is not a class but a primitive type in Java, you can't invoke a method on it.

Second, you want to find duplicate elements, so you should try Set.

Last, if you are new to programming language, you can try Head First Java; otherwise, you may want to have a look at Thinking In Java

Upvotes: 3

vatbub
vatbub

Reputation: 3118

The reason why your code doesn't work is quite obvious: You set checkid to id and then check if they are equal. If you want to check every new id against previous ids, you need to keep track of the ids that were already read, e. g. using a List or a Setas mentioned before.

Something along theese lines would do:

List<Integer> ids = new ArrayList<>();
while (scnr.hasNextInt()) {
    id = scnr.nextInt();
    if (ids.contains(id)) {
       System.out.println("invalid id");
    } else {
        ids.add(id);
        clients.put(new Integer(id), new Client(id));
    }
}

i not understand why String type data can use .matches() but int cannot.

String is a complex datatype, int is a primitive datatype that does not support methods. Anyhow, .matches() wouldn't do the job because it compares against a regular expression. .equals would be a better choice, but again, not for int.

Upvotes: -1

jonD02
jonD02

Reputation: 145

Here's an example that should work for you. Use a HashSet to store ids and check if the Set contains the id.

import java.util.HashSet;
import java.util.Scanner;
import java.util.Set;

public class SetExample {

public static void main(String[] args) {

    Scanner scnr = new Scanner(System.in);
    Set<Integer> ids = new HashSet<>();
    int id;

    while (scnr.hasNextInt()) {
        id = scnr.nextInt();

        if (ids.contains(id)) {
            System.out.println("invalid id");
        } else {
            ids.add(id);
            clients.put(new Integer(id), new Client(id));
        }
    }
}
}

Upvotes: 0

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