Reputation: 494
In my app I have this code allowing the user to select a file :
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType("text/plain");
startActivityForResult(intent,1);
The user can select the .txt file from anywhere in his phone, even from google drive. When the file selection is done I retrieve a Uri object corresponding to the file. The problem is I can't use this Uri to read the file because it is not valid. Here is my code :
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 1) {
if (resultCode == RESULT_OK) {
Uri uri = data.getData();
File file = new File(uri.toString());
try{
InputStream inputStream = new FileInputStream(file);
int content;
while ((content = inputStream.read()) != -1) {
Log.d("===>", String.valueOf((char) content));
}
}catch (Exception e){
Log.d("===>", e.toString());
}
}
}
}
I always get a fileNotFoundException. My question is, is there a way to read the selected file (without knowing in advance the location it will come from). And if not, is there a way to copy the selected file in a folder from which I would easily get it ?
Upvotes: 2
Views: 107
Reputation: 1006644
The problem is I can't use this Uri to read the file because it is not valid.
That is because a Uri
is not a file.
is there a way to read the selected file (without knowing in advance the location it will come from)
The user did not select a file. The user selected a piece of content.
To consume the content represented by the Uri
, call openInputStream()
on a ContentResolver
, passing in the Uri
. This gives you an InputStream
that you can use to read in the content.
Upvotes: 3