CODEWITHSUNDEEP
pythonlambdaparameterscallback
user1654361
user1654361

Reputation: 369

adding parameter to python callback

I am a beginner in Python, and I would like to add a parameter to a callback, in addition to the self and the event. I have tried with lambda, but without success.
My code at the moment looks like this :

control = monitor(block, callback=self.model)

And my model is : 

def model(self, transaction)

I would like to have : 

def model(self, file, transaction)

file being a string parameter I would like to pass to my "model" I tried by changing the control line in : 

control = monitor(block, lambda transaction, args=args:    callback=self.model(transaction, args)

but this does not work, and it is getting too advanced but my python knowledge.
I get the following Error : "SyntaxError: lambda cannot contain assignment", I guess because of the = symbol.

Could you help me by explaining how I should proceed/what I am doing wrong ?

Upvotes: 6

Views: 7776

Answers (1)

Gribouillis
Gribouillis

Reputation: 2220

Many times, when you think about using lambda, it is best to use functools.partial() which performs currying (or curryfication). You can use

from functools import partial

def model(self, transaction, file=None):
    ...

control = monitor(block, callback=partial(self.model, file='foobar'))

To answer your comment below, if you really need a true function, you can design you own:

def callback(func, **kwargs):
    @functools.wraps(func)
    def wrapper(*a, **k):
        return functools.partial(func, **kwargs)(*a, **k)
    return wrapper

control = monitor(block, callback=callback(self.model, file='foobar'))

Upvotes: 10

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