Reputation: 1738
I have a directory-like tree structure in OrientDB:
Node(name='a')->Connection->Node(name='b')->Connection->Node(name='c')
create class Node extends V
create class Connection extends E
let a = create vertex Node set name = 'a'
let b = create vertex Node set name = 'b'
create edge Connection from $a to $b
let c = create vertex Node set name = 'c'
create edge Connection from $b to $c
How can I select Node(name='c') if I know the path 'a'->'b'->'c'?
Keep in mind that all names may be equal on different levels of hierarchy: like instead of 'a', 'b', 'c' it can be 'a', 'a', 'a' but all nodes are different.
Upvotes: 0
Views: 95
Reputation: 1982
try
SELECT expand(o) from
(MATCH
{
class: Node,
where: (name='a')
}
.out('Connection')
.out('Connection')
{
as: o
}
RETURN o)
or without MATCH
select expand(out('Connection').out('Connection')) from Node where name='a'
is this what are you looking for?
Upvotes: 2