CODEWITHSUNDEEP
c++xml-parsingpugixml
skm
skm

Reputation: 5649

Extract all nodes of a node in an XML file by Pugixml C++

I have an XML file with the following structure:

<Employee>
    <Address>
        <Name>XYZ</CustomerName>
        <Street>street no. 1</Street>
        <City>current city</City>
        <Country>country</Country>
    </Address>
</Employee>

I want to extract the values of all the nodes of the node Address and want to store the values in a String Vector (i.e. std::vector<std::string> EmployeeAdressDetails).

How can I extract the nodes in a loop instead of extracting values one by one?

UPDATE: By"Extracting one by one", I mean something like following:

xml_node root_node = doc.child("Employee");
xml_node Address_node = root_node.child("Address");
xml_node Name_node = Address_node .child("Name");
xml_node Street_node = Address_node .child("Street");
xml_node City_node = Address_node .child("City");
xml_node Country_node = Address_node .child("Country");

Upvotes: 0

Views: 2153

Answers (1)

Galik
Galik

Reputation: 48605

You can do this:

for(auto node: doc.child("Employee").child("Address").children())
{
    std::cout << node.name() << ": " << node.text().as_string() << '\n';
}

Or for pre C++11 compilers:

pugi::xml_object_range<pugi::xml_node_iterator> nodes = doc.child("Employee").child("Address").children();

for(pugi::xml_node_iterator node = nodes.begin(); node != nodes.end(); ++node)
{
    std::cout << node->name() << ": " << node->text().as_string() << '\n';
}

Output:

Name: XYZ
Street: street no. 1
City: current city
Country: country

Upvotes: 1

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