Reputation: 243
I installed a CAS server on my server . ( with war deployment in apache tomcat ) . I have my user information like user name and password on that CAS server . ( in the future it will connect to the LDAP or simple relation database for user credential . The problem is here . I want to authenticate my spring application through this CAS server , but I couldn't find any proper configuration for spring security . My config file is :
@Override
protected void configure(HttpSecurity http) throws Exception {
http
.csrf().disable()
.authorizeRequests()
.antMatchers("/assets","/css", "/js","/font-awesome","/bootstrap","/images").permitAll()
.antMatchers("/", "/home").authenticated()
// .antMatchers("/hi").access("hasRole('ROLE_SUBSCRIPTION') or hasRole('ROLE_ADMIN')")
.antMatchers("/edit").authenticated()
// .antMatchers("/playlists/*").authenticated()
// .antMatchers("/createplaylist").authenticated()
.and()
.formLogin()
.loginPage("/login")
.permitAll()
.and()
.logout()
.permitAll();
}
@Bean
public ServiceProperties serviceProperties() {
ServiceProperties sp = new ServiceProperties();
sp.setService(env.getRequiredProperty(CAS_SERVICE_URL));
sp.setSendRenew(false);
return sp;
}
@Bean
public Set<String> adminList() {
Set<String> admins = new HashSet<String>();
String adminUserName = env.getProperty(APP_ADMIN_USER_NAME);
admins.add("admin");
if (adminUserName != null && !adminUserName.isEmpty()) {
admins.add(adminUserName);
}
return admins;
}
@Bean
public AuthenticationUserDetailsService<CasAssertionAuthenticationToken> customUserDetailsService() {
return new CustomUserDetailsService(adminList());
}
@Bean
public CasAuthenticationProvider casAuthenticationProvider() {
CasAuthenticationProvider casAuthenticationProvider = new CasAuthenticationProvider();
// casAuthenticationProvider.setAuthenticationUserDetailsService(customUserDetailsService());
// casAuthenticationProvider.setServiceProperties(serviceProperties());
casAuthenticationProvider.setTicketValidator(cas20ServiceTicketValidator());
// casAuthenticationProvider.setKey("an_id_for_this_auth_provider_only");
return casAuthenticationProvider;
}
@Bean
public Cas20ServiceTicketValidator cas20ServiceTicketValidator() {
return new Cas20ServiceTicketValidator(env.getRequiredProperty(CAS_URL_PREFIX));
}
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
// auth.inMemoryAuthentication().withUser("admin").password("admin").roles("ADMIN");
auth.authenticationProvider(casAuthenticationProvider());
}
Upvotes: 1
Views: 905
Reputation: 243
Well I found an easy auto configuration for Cas client on GitHub for spring with just two movement :) first add the dependency second just add an annotation https://github.com/Unicon/cas-client-autoconfig-support
Upvotes: 1
Reputation: 1
@kaveh.n I hope you are getting a 403 error while accessing your service. If this is your issue, authentication entry point is the missing part in your configuration. Please follow the spring tutorial for the configuration http://docs.spring.io/spring-security/site/docs/3.1.4.RELEASE/reference/cas.html#cas-how-it-works
Upvotes: 0
Reputation: 2699
You may want to use pac4j to have an easy configuration: https://github.com/pac4j/spring-security-pac4j and http://www.pac4j.org/1.9.x/docs/clients/cas.html
Examples: https://github.com/pac4j/spring-security-pac4j-demo/blob/master/src/main/resources/securityContext.xml#L158 or https://github.com/pac4j/spring-security-pac4j-boot-demo/blob/master/src/main/java/org/pac4j/demo/spring/SecurityConfig.java#L244
Upvotes: 0