Reputation: 928
I have following table:
ID | source | Name | Age | ... | ...
1 | SQL | John | 18 | ... | ...
2 | SAP | Mike | 21 | ... | ...
2 | SQL | Mike | 20 | ... | ...
3 | SAP | Jill | 25 | ... | ...
I want to have one record for each ID. The idea behind this is that if the ID comes only once (no matter the Source), that record will be taken. But, If there are 2 records for one ID, the one containing SQL as source will be the used record here.
So, In this case, the result will be:
ID | source | Name | Age | ... | ...
1 | SQL | John | 18 | ... | ...
2 | SQL | Mike | 20 | ... | ...
3 | SAP | Jill | 25 | ... | ...
I did this with a partition over (ordered by Source desc), but that wouldn't work well if a third source will be added one day.
Any other options/ideas?
Upvotes: 3
Views: 309
Reputation: 81970
You can use the WITH TIES clause and the window function Row_Number()
Select Top 1 With Ties *
From YourTable
Order By Row_Number() over (Partition By ID Order By Case When Source = 'SQL' Then 0 Else 1 End)
Upvotes: 4
Reputation: 460168
The easiest approach(in my opinion) is using a CTE with a ranking function:
with cte as
(
select ID, source, Name, Age, ... ,
rn = row_number() over (partition by ID order by case when source = 'sql'
then 0 else 1 end asc)
from dbo.tablename
)
select ID, source, Name, Age, ...
from cte
where rn = 1
Upvotes: 4
Reputation: 70658
You can use ROW_NUMBER
:
WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER( PARTITION BY ID
ORDER BY CASE WHEN [Source] = 'SQL' THEN 1 ELSE 2 END)
FROM dbo.YourTable
)
SELECT *
FROM CTE
WHERE RN = 1;
Upvotes: 4
Reputation: 138
How about
SELECT *
FROM table
WHERE ID in (
SELECT ID FROM test
group by ID
having count(ID) = 1)
OR source = 'SQL'
Upvotes: 3