Reputation: 83
I created a directory named mypack and added a Java file inside that directory named as A.java . The code for A.java is as follows:
package mypack;
public class A{
public A(){
System.out.println("Inside A");
}
}
And I added another file in the same directory named Demo.java . The code for this file is as follows:
package mypack;
public class Demo {
public static void main(String args[]) {
A a = new A();
}
}
The problem is when I compile the second file Demo.java I get error as such : cannot find symbol A
the directory mypack looks like this :
I don't know why Demo.java the file of the same package (mypack) as that of A.java can't access class A even when I declared it as public in A.java. Please somebody help!!
Upvotes: 0
Views: 1112
Reputation: 16
Maybe you can use
javac *.java
to complie two java source files at once.
Upvotes: 0
Reputation: 4647
You could do something like this to compile the files that are needed, just as the case you have mentioned in your question:
javac Demo.java A.java
This compiles your class along with the dependency A.java
in this case.
Or you could do something like this, to cover all the .java
files that you have under your directory.
javac *.java
Please refer to this for further reference!
Upvotes: 0
Reputation: 153
To compile the file, open your terminal and type
javac filename.java
To run the generated class file, use
java filename
Upvotes: 0