CODEWITHSUNDEEP
c++listsplice
Hano
Hano

Reputation: 19

In C++ standard, Why Infinite loop occurs when i use list.begin() as list.splice()'s first and third parameters at the same time

When I use begin() as list.splice()'s first and third parameters at the same time, I don't know why output has infinite loop.

#include <list>
#include <iostream>
#include <iterator>
using namespace std;

int main() {
    list<int> mylist;
    for (int i = 1; i < 10; i++)
        mylist.push_back(i);
    mylist.splice(mylist.begin(), mylist, mylist.begin(), mylist.end());

    for (auto it = mylist.begin(); it != mylist.end(); it++) {
        cout << *it << " ";
    }
}

Upvotes: 0

Views: 525

Answers (1)

grek40
grek40

Reputation: 13438

The code exhibits undefined behavior:

Exception safety

(...) if (...) position is in the range [first,last) in (3), it causes undefined behavior.

That doesn't exactly explain why the infinite loop occurs but it explains why an infinite loop is a possible behavior.

Upvotes: 1

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