CODEWITHSUNDEEP
c++
Rob Tyson
Rob Tyson

Reputation: 3

Receiving an "Exception Thrown" during loop

The exception I have received was 

Exception thrown at 0x70F8516F (vcruntime140d.dll) in Project.exe: 0xC0000005: Access violation writing location 0x723D9C18.

It occurs during the final iteration of user defined information into an array during a for loop: 

int k;
cout << "Enter array size:";
cin >> k;
while (k > 3) {

    cout << "Array size too big, please reenter" << endl;
    cin >> k;

}

Player *ptr = new Player[k];

string n;
int s;

for (int i = 0; k >= i; i++) {

    cout << "Enter name" << endl;
    cin >> n;
    ptr[i].setName(n);

    cout << "Enter score" << endl;
    cin >> s;
    ptr[i].setScore(s);

    ptr[i].getName();
    ptr[i].getScore();

}

And it directs me to the end of my setName function

void Player::setName(string n) {

    name = n;

}

Upvotes: 0

Views: 71

Answers (2)

Neer Patel
Neer Patel

Reputation: 440

You should write 

Player *ptr = new Player[k+1];

Suppose your value of k is 5 then your loop will iterate 6 times (0 to 5) , and you have allocated space only for 5 objects. That's why it will throw an exception.

Upvotes: 0

IAmBlake
IAmBlake

Reputation: 457

your array size should be (k+1) or the for loop should be like :

for (int i = 0; i<k; i++) {

cout << "Enter name" << endl;
cin >> n;
ptr[i].setName(n);

cout << "Enter score" << endl;
cin >> s;
ptr[i].setScore(s);

ptr[i].getName();
ptr[i].getScore();

}

Upvotes: 1

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