CODEWITHSUNDEEP
pythonpython-3.x
Jun Min Kim
Jun Min Kim

Reputation: 275

Way to quit the most outer function from an inner function?

Let's say I have code that looks like this:

def lab():
    letter = prompt() 
    def experiment_1():
        if letter == 1:
            print("check")
            #Would there be a way to quit the lab function right here?
    def experiment_2():
        if letter == 1:
            print("check2")

    experiment_1()
    experiment_2()
lab()

Would there be a way for me to quit the lab function right after I print "check"? I tried putting return at the end of experiment_1 but that just seems to go right to the next function which is experiment_2.

Upvotes: 11

Views: 6010

Answers (3)

warvariuc
warvariuc

Reputation: 59654

The most obvious way is to raise an exception. It will allow you to get out from any depth. Define a custom exception and catch it at some outer level. For example:

class MyError(Exception):
    pass

def _lab():
    letter = prompt() 

    def experiment_1():
        if letter == 1:
            print("check")
            raise MyError

    def experiment_2():
        if letter == 1:
            print("check2")

    experiment_1()
    experiment_2()

def lab():
    try:
        return _lab()
    except MyError:
        return

lab()

This particular example is kind of ugly, but you should get the idea.

Upvotes: 13

Angel F
Angel F

Reputation: 489

You can put return statement just in the place that you want to function ends. In you can returns any other thin would be return var1 var2

def lab():
    letter = prompt() 
    def experiment_1():
        if letter == 1:
            print("check")
            # Would there be a way to quit the lab function right here?
            # you have to put return just here
            return
    def experiment_2():
        if letter == 1:
            print("check2")

    experiment_1()
    experiment_2()
lab()

Upvotes: -2

Gabriel
Gabriel

Reputation: 1942

As said in comments section, you can pass a flag to the outer function

def lab():
    letter = prompt()

    def experiment_1():
        if letter == 1:
            print("check")
            return True
        return False

    def experiment_2():
        if letter == 1:
            print("check2")

    if experiment_1():
        return

    experiment_2()

lab()

But you should improve your question because it sounds like you are trying to solve another problem. See: http://mywiki.wooledge.org/XyProblem

Upvotes: 1

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