CODEWITHSUNDEEP
javacharascii
Lost_in_the_code
Lost_in_the_code

Reputation: 75

How to add a numerical value for a char in Java

I have this code where I want to add the value 97 for a char variable, but instead to obtain, according with ASCII table, the final number 98 for the letter 'b' the output is 205.

What is wrong in my code?

public class MyTest {

    public static void main(String[] args) {

        char result;
        String input = "blablab";

        result = charCounter(input);

    }

    private static char charCounter(String input) {

        int[] array = new int[26];

        for (int i = 0; i < input.length(); i++) {
            char ch = input.charAt(i);

            array[ch - 97]++;

        }

        int max = array[0];
        for (int i = 1; i < array.length; i++) {

            if (array[i] > max) {
                max = array[i];
                char frequent = input.charAt(i);

                System.out.println(frequent + 97);

            }

        }

        return 45;
    }

}

Thank you for your help.

Upvotes: 0

Views: 1885

Answers (1)

nail fei
nail fei

Reputation: 2329

replace

System.out.println(frequent + 97);

with

System.out.println((char)(i + 97));

because 

char + Integer = Integer

so you have to convert it to char and the ascii of corresponding char should be

i + 97

rather than 

frequent + 97

Upvotes: 1

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