CODEWITHSUNDEEP
carrayspointersstruct
balaji ji
balaji ji

Reputation: 1

Pass struct member array to function in C

static void fill_array(int arr[], int count, int num)
{
    int i;
    for(i=0; i<count; i++)
    {
        arr[i] = num;
    }    
}

typedef struct
{
    int a[10];
} x;

int main(void) {
    x *x1;
    fill_array(x1->a, 10, 0);
}

While trying this I am getting Runtime error. Can anybody help on this issue? Thanks in advance.

Upvotes: 0

Views: 53

Answers (3)

MayurK
MayurK

Reputation: 1957

You have not allocated memory for x1.

int main(void) {
    x *x1 = malloc(sizeof(x));

    if(0 !=x1)
    {
        fill_array(x1->a, 10, 0);
        free(x1);
    }
}

Upvotes: 1

Zouz
Zouz

Reputation: 36

Your runtime error should be probably a segmentation fault

I can look your first pointeur x *x1;

Wich is not allocated and you are trying to access to the content of a non-allocated pointeur so ... segfault.

There is 2 solution. declare your structure with local memory x x1; or allocate it

Upvotes: -1

Bathsheba
Bathsheba

Reputation: 234875

You didn't allocate any memory for x: the behaviour of your program is undefined.

For this example, you could get away with

x x1;
fill_array(x1.a, 10, 0);

i.e. use automatic storage duration for x. This is because x1.a effectively decays to a pointer when passed to the function fill_array.

Upvotes: 1

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