CODEWITHSUNDEEP
javascriptangularjsselectng-options
CuriousMind
CuriousMind

Reputation: 195

Making ng-options dynamic in AngularJS

I have an array as follows:

$scope.age = 2;
$scope.people = [{name:"Sam",age:2},{name:"Pam",age:3},{name:"Ham",age:4}]

I want the ng-options to be dynamic i.e., If the age is 2 then show all objects of people in ng-options. If the age is 1 then show object with name as "Sam".

$scope.age can have value either 1 or 2.

How can I do this in AngularJS without writing different block of select statements?

Upvotes: 2

Views: 3369

Answers (3)

Aruna
Aruna

Reputation: 12022

You can use AngularJS filter as below with a custom function.

Working sample: (type 1 or 2 in the textbox below to test this)

var app = angular.module('app', []);

app.controller('TestController', function($scope) {
  $scope.age = 2;
  $scope.people = [{name:"Sam",age:2},{name:"Pam",age:3},{name:"Ham",age:4}];
  $scope.filterPeople = function(person) {
     return $scope.age === 2 || person.name === "Sam";
  };
});

angular.bootstrap(document, ['app']);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-controller="TestController">
  Age: <input type="text" ng-model="age" />
  <select ng-options="person as person.name for person in people | filter:filterPeople" ng-model="selected">
  </select>
</div>

Upvotes: 0

devqon
devqon

Reputation: 13997

The ng-options directive can also parse filters, so you can do something like this:

<select ng-options="person as person for person in people | filter:{age:age}">
</select>

See this jsfiddle

Upvotes: 0

Robba
Robba

Reputation: 8324

You could bind the select to the result of a function:

<select ng-options="person as person for person in getPersons()">
</select>

Then setup your scope like this:

$scope.age = 2;
$scope.people = [{name:"Sam",age:2},{name:"Pam",age:3},{name:"Ham",age:4}]
$scope.getPersons = function() {
    if ($scope.age = 1)
        return $scope.people.filter(function(item) {
            item.name == "Sam";
        });
    else
        return $scope.people;
};

Upvotes: 1

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