CODEWITHSUNDEEP
clojurefunctional-programminglispread-eval-print-loop
Ertuğrul Çetin
Ertuğrul Çetin

Reputation: 5231

repl/source function does not work in Clojure

I'm trying with files not REPL.

Here is my clj file:

tests.my-clj-file.clj

(ns tests.my-clj-file
  (:require [clojure.repl :as repl]))

(defn my-fn
  []
  1)

(println (repl/source my-fn))


The output is:

Source not found
nil

Upvotes: 2

Views: 316

Answers (2)

Nathan Davis
Nathan Davis

Reputation: 5766

If you try (doc repl/source), you'll get something like this (emphasis added):

Prints the source code for the given symbol, if it can find it. This requires that the symbol resolve to a Var defined in a namespace for which the .clj is in the classpath.

So clojure.repl/source only works with code that has been loaded from source files. It won't work if you enter the code in the REPL (regardless whether the code is in a file).

Upvotes: 0

user2609980
user2609980

Reputation: 10474

It is only possible to read the source from Vars that are on disk.

So if you have evaluated the buffer it is loaded in the REPL and you cannot view the source with source.

One way to accomplish reading the source is by placing my-fn in another file (e.g., /my_other_clj_file.clj):

(ns my-other-clj-file)

(defn my-fn
  []
  1)

Do not evaluate the buffer.

Then go to /tests/my_clj_file.clj and evaluate:

(ns tests.my-clj-file
  (:require [clojure.repl :as repl]
            [other-file :refer [my-fn]))

(println (repl/source my-fn))

This does correctly print the source.

(defn my-fn
  []
  1)
nil

Upvotes: 1

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