CODEWITHSUNDEEP
javaarraysstring
Tinus Jackson
Tinus Jackson

Reputation: 3653

Splitting string into different arrays of types using regex

What's the easiest and most effective way to spit a string into different arrays of types? Example: 

String[] textArr; 
String[] numbersArr;

and if possible a String[] doubleArr and a String[] dateArrayz

//the string I want to split
String splitMe = "Tinus has 99 issues and has to pay $2200.50 for 26 on 2016/10/10";

After it's split it should be 

String[] textArr = ["Tinus","has","issues","and","to","pay","for","on"]; 
String[] numbersArr = ["99","26"];
String[] doubleArr = ["2200.50"];
String[] dateArr = ["2016/10/10"];

Upvotes: 0

Views: 51

Answers (2)

Nurjan
Nurjan

Reputation: 6063

You can try something like this:

String splitMe = "Tinus has 99 issues and has to pay $2200.50 for 26 on 2016/10/10";


String[] splitArray = splitMe.split(" ");
System.out.println("splitArray: " + Arrays.toString(splitArray));

String[] tmp = new String[splitArray.length];        

int i = 0;
for (String s : splitArray) {
    if (s.matches("[A-Za-z]+")) {
        tmp[i] = s;
        i++;
    }         
}     

String[] textArr = new String[i];
for (int j = 0; j < textArr.length; j++) {
    textArr[j] = tmp[j];
}

tmp = new String[splitArray.length];

i = 0;
for (String s : splitArray) {
    if (s.matches("[0-9]+")) {
        tmp[i] = s;
        i++;
    } 
}

String[] numbersArr = new String[i];
for (int j = 0; j < numbersArr.length; j++) {
    numbersArr[j] = tmp[j];
}

tmp = new String[splitArray.length];

i = 0;
for (String s : splitArray) {
    if (s.matches("\\$[0-9]+\\.[0-9]+")) {
        tmp[i] = s;
        i++;
    } 
}

String[] doubleArr = new String[i];
for (int j = 0; j < doubleArr.length; j++) {
    doubleArr[j] = tmp[j];
}

tmp = new String[splitArray.length];

i = 0;
for (String s : splitArray) {
    if (s.matches("[0-9]+/[0-9]+/[0-9]+")) {
        tmp[i] = s;
        i++;
    }
}

String[] dateArr = new String[i];
for (int j = 0; j < dateArr.length; j++) {
    dateArr[j] = tmp[j];
}

System.out.println("textArr: " + Arrays.toString(textArr));
System.out.println("numbersArr: " + Arrays.toString(numbersArr));
System.out.println("doubleArr: " + Arrays.toString(doubleArr));
System.out.println("dateArr: " + Arrays.toString(dateArr));

Please note that the regex used are not ideal but they work for your case. I used arrays because I thought it is a strict requirement. You can use lists as well which is better.

Upvotes: 0

Tim Biegeleisen
Tim Biegeleisen

Reputation: 521534

I might opt for just splitting the input string by space, and then using a pattern match to check each entry to determine where it belongs:

String splitMe = "Tinus has 99 issues and has to pay $2200.50 for 26 on 2016/10/10";
String[] parts = splitMe.split(" ");
List<String> textList = new ArrayList<>();
List<String> numbersList = new ArrayList<>();
List<String> currencyList = new ArrayList<>();
List<String> dateList = new ArrayList<>();

for (String part : parts) {
    if (part.matches("\\d*")) {
        numbersList.add(part);
    }
    else if (part.matches("\\$\\d*\\.\\d*")) {
        currencyList.add(part);
    }
    else if (part.matches("\\d{4}/\\d{2}/\\d{2}")) {
        dateList.add(part);
    }
    else {
        textList.add(part);
    }
}

I didn't attempt to formally extract a double from the currency. And I also chose to use lists rather than arrays to store the various terms, because this will scale better. I will leave it up to you to fill in the details.

Upvotes: 4

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