Reputation: 1123
How do we declare a single byte variable in Python? I would like to achieve the following result represented in C:
unsigned char c = 0xFF;
I would like to know if it is possible to declare an 8-bit variable in Python.
Upvotes: 24
Views: 50159
Reputation: 416
The answer depends on the python version.
$ python
Python 2.7.5 (default, Mar 20 2020, 17:08:22) ...
>>> myba = bytes([0])
>>> myba[0]
'['
>>> myba = bytearray([0])
>>> myba[0]
0
>>>
$ python3
Python 3.6.8 (default, May 6 2020, 12:04:35) ...
>>> myba = bytes([0])
>>> myba[0]
0
>>> myba = bytearray([0])
>>> myba[0]
0
>>>
Upvotes: 0
Reputation: 416
The answer depends on python version.
$ python3
Python 3.6.8 (default, May 6 2020, 12:04:35)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-39)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> myba = bytes([0])
>>> myba[0]
0
>>>
$ python
Python 2.7.5 (default, Mar 20 2020, 17:08:22)
[GCC 4.8.5 20150623 (Red Hat 4.8.5-39)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> myba = bytes([0])
>>> myba[0]
'['
>>>
Upvotes: 0
Reputation: 155418
Python doesn't differentiate between characters and strings the way C does, nor does it care about int
bit widths. For a single byte, you basically have three choices:
bytes
(or bytearray
) object mychar = b'\xff'
(or mychar = bytearray(b'\xff')
)int
that you don't assign values outside range(256)
(or use masking to trim overflow): mychar = 0xff
ctypes
type, e.g. mychar = ctypes.c_ubyte(0xff)
The final option is largely for dealing with C functions through ctypes
, it's otherwise slow/not Pythonic. Choosing between options 1 and 2 depends on what you're using it for; different use cases call for different approaches (though indexing/iterating the bytes
object would get you the int
values if you need to use both forms).
Upvotes: 30