CODEWITHSUNDEEP
python
user3698773
user3698773

Reputation: 1039

read contents of a file from a list of file with os.listdir() (python)

I need to read the contents of a file from the list of files from a directory with os.listdir. My working scriptlet is as follows:

import os

path = "/Users/Desktop/test/"
for filename in os.listdir(path):
    with open(filename, 'rU') as f:
      t = f.read()
      t = t.split()
      print(t)

print(t) gives me all the contents from all the files at once present in the directory (path).

But I like to print the contents on first file, then contents of the second and so on, until all the files are read from in dir.

Please guide ! Thanks.

Upvotes: 0

Views: 4863

Answers (3)

hiro protagonist
hiro protagonist

Reputation: 46859

os.listdir returns the name of the files only. you need to os.path.join that name with the path the files live in - otherwise python will look for them in your current working directory (os.getcwd()) and if that happens not to be the same as path python will not find the files:

import os

path = "/Users/Desktop/test/"

for filename in os.listdir(path):
    print(filename)
    file_path = os.path.join(path, filename)
    print(file_path)
    ..

if you have pathlib at your disposal you can also:

from pathlib import Path

path = "/Users/Desktop/test/"

p = Path(path)
for file in p.iterdir():
    if not file.is_file():
            continue
    print(file)
    print(file.read_text())

Upvotes: 1

Fomalhaut
Fomalhaut

Reputation: 9745

First, you should find the path of each file using os.path.join(path, filename). Otherwise you'll loop wrong files if you change the variable path. Second, your script already provides the contents of all files starting with the first one. I added a few lines to the script to print the file path and an empty line to see where the contents end and begin:

import os

path = "/Users/Desktop/test/"

for filename in os.listdir(path):
    filepath = os.path.join(path, filename)
    with open(filepath, 'rU') as f:
        content = f.read()
        print(filepath)
        print(content)
        print()

Upvotes: 1

optimus prime
optimus prime

Reputation: 774

You can print the file name. Print the content after the file name.

import os

path = "/home/vpraveen/uni_tmp/temp"

for filename in os.listdir(path):

    with open(filename, 'rU') as f:
      t = f.read()
      print filename + " Content  : "
      print(t)

Upvotes: 1

Related Questions