CODEWITHSUNDEEP
xmlxsltxpath
Andrea
Andrea

Reputation: 1

XML Xpath XSL Return more than one value when node name are the same

I have an XML, with a XSLT I try to extract values. It works, but the expression value-of select in the XSL returns only the first value "Al Pacino". How can I use it to have all the <Cast> values?

 <Questionario>
  <Video ID="1" Titolo="Scarface">
   <Cast>Al Pacino</Cast>
   <Cast>Steven Bauer</Cast>
   <Cast>Michelle Pfieffer</Cast>
   <Genere>azione e avventura</Genere>
    <Sottogenere>crime action</Sottogenere>
    <Sottogenere>Thriller</Sottogenere>
    <Sottogenere>Gangster</Sottogenere>

XSL

<xsl:stylesheet version="1.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
        <html>
        <head>
            <title>Report Questionari Slow TV</title>
        </head>
        <body>
            <h3>Video Visionati</h3>
            <div>
                <xsl:apply-templates select="//Video"> 
                </xsl:apply-templates>

            </div>


        <xsl:for-each select="Questionario/Video">

                <xsl:value-of select="@Titolo"/>

                 <xsl:value-of select="Cast"/>

Upvotes: 0

Views: 288

Answers (1)

Tim C
Tim C

Reputation: 70638

You are doing this to output the Cast

<xsl:value-of select="Cast"/>

In XSLT 1.0 this will only select the first Cast element, but you have multiple ones. Try using xsl:for-each instead

<xsl:for-each select="Cast">
     <xsl:value-of select="." />
     <br />
</xsl:for-each>

Alternatively you could use templates.

<xsl:apply-templates select="Cast" />

You would then need a template to match this

<xsl:template match="Cast">
     <xsl:value-of select="." />
     <br />
</xsl:template>

Upvotes: 2

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