Reputation: 27216
I need a function with type Pipe a b m r -> Pipe (a, c) (b, c) m r
.
But no matter how much I play with for
, ~>
or >~
; I can not match the types properly.
Can you help me?
Upvotes: 1
Views: 102
Reputation: 152682
I don't think it's possible in general. Suppose we did manage to write it:
hypotheticalLift :: Pipe a b m r -> Pipe (a, c) (b, c) m r
What behavior should hypotheticalLift (yield b)
have? Presumably it should be the same as yield (b, c)
for some c
-- but which c
, and why?
Upvotes: 4