CODEWITHSUNDEEP
python
Fab
Fab

Reputation: 1215

Python. Call a function inside another function

I have the following piece of code. 

 def num_dim(response_i, m):

   for response_j in response_i['objcontent']:
      if response_i['objkey']== 'explorecube_dimvalues':
         mm = [response_j['title']]
         m.append(mm)

   m=(len(m))
   return m


if __name__=='__main__':

    for response_i in response['response']:
        m=[ ]
        x=0
        def num_dim_2(response_i, m):
           if response_i['objkey']== 'explorecube_dimvalues':
               m = num_dim(response_i, m)
               print(m)
           return m
        num_dimentions= num_dim_2 (response_i, m)
        print(num_dimentions)

The output for print(m) is:

3

but the output for print(num_dimentions) is:

[ ] 
[ ]
3
[ ]

which I expected only 3.

Anyone knows how can I fix this issue (get the value of 3 as the final output). Thank you.

Upvotes: 0

Views: 82

Answers (1)

Vijayakumar Udupa
Vijayakumar Udupa

Reputation: 1145

This is because of below piece of code.

def num_dim_2(response_i, m):
           if response_i['objkey']== 'explorecube_dimvalues':
               m = num_dim(response_i, m)
               print(m)
           return m

Even if if condition fails, return m statement is still executed, which will return a blank list.

Further you are executing print(num_dimentions) inside a loop, which means value gets printed as many times as loop is executed. If you need only one output, you will have to print it based on some condition.

Note: its really not good programming practice to use same variable names and also reuse variable names with different type (ex: in num_dim, m is a list and suddenly m is some integer!)

Upvotes: 3

Related Questions