Reputation: 2268
I can't figure out how to store the result from cell magic - %%timeit
? I've read:
and in this questions answers only about line magic. In line mode (%
) this works:
In[1]: res = %timeit -o np.linalg.inv(A)
But in cell mode (%%
) it does not:
In[2]: res = %%timeit -o
A = np.mat('1 2 3; 7 4 9; 5 6 1')
np.linalg.inv(A)
It simply executes the cell, no magic. Is it a bug or I'm doing something wrong?
Upvotes: 17
Views: 9181
Reputation: 71
If you just care about the output of the cell magic, e.g. for recording purposes - and you don't need the extra metadata included in the TimeitResult object, you could also just combine it with %%capture:
%%capture result
%%timeit
A = np.mat('1 2 3; 7 4 9; 5 6 1')
np.linalg.inv(A)
Then you can grab the output from result.stdout, which will yield whatever the output of the cell is - including the timing result.
print(result.stdout)
'26.4 us +- 329 ns per loop (mean +- std. dev. of 7 runs, 10000 loops each)\n'
This works for arbitrary cell magic, and can work as a fallback if the underscore solution isn't working.
Upvotes: 2
Reputation: 152735
You can use the _
variable (stores the last result) after the %%timeit -o
cell and assign it to some reusable variable:
In[2]: %%timeit -o
A = np.mat('1 2 3; 7 4 9; 5 6 1')
np.linalg.inv(A)
Out[2]: blabla
<TimeitResult : 1 loop, best of 3: 588 µs per loop>
In[3]: res = _
In[4]: res
Out[4]: <TimeitResult : 1 loop, best of 3: 588 µs per loop>
I don't think it's a bug because cell mode commands must be the first command in that cell so you can't put anything (not even res = ...
) in front of that command.
However you still need the -o
because otherwise the _
variable contains None
.
Upvotes: 24