CODEWITHSUNDEEP
djangopython-2.7django-views
Sharan Kumar
Sharan Kumar

Reputation: 15

URL Error in Django,Page not found 404

This is my views.py :

from django.http import Http404 
from django.shortcuts import render
from .models import Album


def index(request):
    all_albums = Album.objects.all()
    return render(request, 'music/index.html', {'all_albums': all_albums})


def detail(request, album_id):
    try:
        album = Album.objects.get(pk=album_id)
    except Album.DoesNotExist:
        raise Http404("Album does not exist")
    return render(request, '/music/detail.html', {'album': album})

This is my music\urls.py :

from django.conf.urls import url
from . import views

urlpatterns = (
    url(r'^$', views.index, name='index'),
    url(r'^(?P<album_id>[0-9]+)/$', views.detail, name='detail'),
)

When I am running this code, I am getting the error as :

error image

Upvotes: 0

Views: 163

Answers (1)

neverwalkaloner
neverwalkaloner

Reputation: 47374

As stacktrace said you are trying to open http://127.0.0.1/music/id/1 page not http://127.0.0.1/music/1 but there is no such urp pattern in your urls.py. You need try to open http://127.0.0.1/music/1 or add new pattern:

url(r'^id/(?P<album_id>[0-9]+)/$', views.detail, name='detail')

to see http://127.0.0.1/music/id/1 page.

Upvotes: 1

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