CODEWITHSUNDEEP
wpfdatagrid
Nikhil
Nikhil

Reputation: 181

WPF Datagrid autogenerated columns

I have bound a datatable to a datagrid in WPF. Now on clicking a row in the grid I need to have a window pop up. But for that, I need to first change a column in the datagrid to be a hyperlink. Any ideas on how to do that?

<DataGrid Name="dgStep3Details" Grid.Column="1" Margin="8,39,7,8" IsReadOnly="True" ItemsSource="{Binding Mode=OneWay, ElementName=step3Window,Path=dsDetails}" />

If I can't change an autogenerated column to hyperlink, is there a way to add a button to each row instead?

Thanks Nikhil

Upvotes: 1

Views: 2910

Answers (2)

Nikhil
Nikhil

Reputation: 181

So, it was really hard to create hyperlink columns to autogenerated datagrid. What I eventually did was this - create buttons to the grid on the fly and then attach a routed event for the same based on the autogenerate event of the datagrid where I shall put my code. I didn't want my code to be hardcoded to the columns and now I'm flexible by changing the datatable on the fly. Here is the code:

 private void dgStep3Details_AutoGeneratedColumns(object sender, EventArgs e)
    {

        DataGrid grid = sender as DataGrid;
        if (grid == null)
            return;
        DataGridTemplateColumn col = new DataGridTemplateColumn();
        col.Header = "More Details";
        FrameworkElementFactory myButton = new FrameworkElementFactory(typeof(Button), "btnMoreDetails");
        myButton.SetValue(Button.ContentProperty, "Details");
        myButton.AddHandler(Button.ClickEvent, new RoutedEventHandler(btnMoreDetails_Click));
        DataTemplate cellTempl = new DataTemplate();
        //myButton.SetValue(Button.CommandParameterProperty, ((System.Data.DataRowView)((dgStep3Details.Items).CurrentItem)).Row.ItemArray[0]);
        cellTempl.VisualTree = myButton;
        col.CellTemplate = cellTempl;
        dgStep3Details.Columns.Add(col);

    }
    public void btnMoreDetails_Click(object sender, RoutedEventArgs e)
    {
        //Button scrButton = e.Source as Button;
        string currentDetailsKey = ((System.Data.DataRowView)(dgStep3Details.Items[dgStep3Details.SelectedIndex])).Row.ItemArray[0].ToString();
        // Pass the details key to the new window

    }

Upvotes: 1

Lane
Lane

Reputation: 2719

I don't think you'll be able to get these advanced UI features out of autogenerated columns. I think you'll either have to decide to program these columns in C# or VB.NET when you retrieve your data and tailor them the way you like, or you'll have to abandon the UI ideas you've mentioned. Autogenerated columns just cannot do that.

However, you could change your approach. Try checking into events like MouseLeftButtonDown, etc. and see if you can simulate the behavior you want by other means.

Upvotes: 0

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