CODEWITHSUNDEEP
javascriptstringcountcharacter
tss1
tss1

Reputation: 11

Javascript if characters in a string has the same count occurance

How to find if all distinct characters in a sting have the same count for example aassdd has the same count of 'a', 's' and 'd'. I know how to compare characters to each other but i don't know where to hold the numbers of each occurance

  function letterCount(string, letter, caseSensitive) {
      var count = 0;
      if ( !caseSensitive) {
        string = string.toUpperCase();
        letter = letter.toUpperCase();
      }
      for (var i=0, l=string.length; i<string.length; i += 1) {
        if (string[i] === letter) {
            count += 1;
        }
      }
      return count;
    }

My question is how to hold the number of each character occurance and than to compare them

Upvotes: 0

Views: 128

Answers (1)

Nina Scholz
Nina Scholz

Reputation: 386540

You could use an object and the characters as property for count.

function letterCount(string, caseSensitive) {
    var count = {};
    if (!caseSensitive) {
        string = string.toUpperCase();
    }
    for (var i = 0, l = string.length; i < l; i++) {
        if (!count[string[i]]) {
            count[string[i]] = 0;
        }
        count[string[i]]++;
    }
    return count;
}

console.log(letterCount('aAssdD', false));
console.log(letterCount('aAssdD', true));

Upvotes: 2

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