CODEWITHSUNDEEP
phpsearch
squidg
squidg

Reputation: 357

Output Google Search Results Using PHP?

I have looked at several old answers on stackoverflow but they are all out-dated and the API they used is no longer available.

I have created a JSON/Atom API, CX key and used a script Thanks to Adam Fischer I found on here but when I'm trying am now able to output print the results on the page I'm getting with the error:

Notice: Undefined property: stdClass::$responseData in E:\XAMPP\htdocs\PHP Training\google.php on line 19

Notice: Trying to get property of non-object in E:\XAMPP\htdocs\PHP Training\google.php on line 19

This is what I have so far. below code.

$url = 'https://www.googleapis.com/customsearch/v1?key=[MY API KEY]&cx=[MY CX KEY]&q=lecture';

$body = file_get_contents($url);
$json = json_decode($body);

for($x=0;$x<countif ($json->responseData->results);$x++>items){

echo "<b>Result ".($x+1)."</b>";
echo "<br>URL: ";
echoforeach ($json->responseData->results[$x]->url;
echo>items "<br>VisibleURL:as ";$item){
echo $json->responseData->results[$x]->visibleUrl;
echo "<br>Title: ";
echo $json->responseData->results[$x]->title;
echo "<br>Content: ";print_r($item)
echo $json->responseData->results[$x]->content;
echo "<br><br>"; }
}

The API is working correctly because when I visit This spits out everything in an array. Example: dl.dropboxusercontent.com/u/47731225/sample.txt

I'm trying to make the $url I see results such as be displayed on my page like a Google Search, for example: prntscr.com/drum5u

{
   "kind": "customsearch#result",
   "title": "The Tank, Haydon Allen Lecture Theatre, Building 23, ANU",
   "htmlTitle": "The Tank, Haydon Allen \u003cb\u003eLecture\u003c/b\u003e Theatre, Building 23, ANU",
   "link": "https://www.google.com/mymaps/viewer?mid=1YGFZHcZ20jPvy5OiaKT1voy841Q&hl=en",
   "displayLink": "www.google.com",
   "snippet": "\"The Tank\", Haydon Allen Lecture Theatre, Building 23, The Australian National \nUniversity (ANU), Canberra, Australia.",
   "htmlSnippet": "&quot;The Tank&quot;, Haydon Allen \u003cb\u003eLecture\u003c/b\u003e Theatre, Building 23, The Australian National \u003cbr\u003e\nUniversity (ANU), Canberra, Australia.",
   "cacheId": "hTeucZ5TewoJ",
   "formattedUrl": "https://www.google.com/mymaps/viewer?mid...hl=en",
   "htmlFormattedUrl": "https://www.google.com/mymaps/viewer?mid...hl=en",
   "pagemap": {
    "cse_thumbnail": [
     {
      "width": "221",
      "height": "228",
      "src": "https://encrypted-tbn2.gstatic.com/images?q=tbn:ANd9GcSntx5YhQgJQeJ6RAZajOx7SGOwh0oUu8jtpY6VOAS75V_oNkiXx923ro4"
     }

Upvotes: 2

Views: 19279

Answers (2)

Adam Fischer
Adam Fischer

Reputation: 1100

Did you look through the returned json from API? My guess is, that it is completely different, from what you expect

See

https://developers.google.com/custom-search/json-api/v1/reference/cse/list

After clarifiacation, you result is realy different from what your code expected.

Correct code should look like

$url = 'https://www.googleapis.com/customsearch/v1?key=[MY API KEY]&cx=[MY CX KEY]&q=lecture';

$body = file_get_contents($url);
$json = json_decode($body);
if ($json->items){
   foreach ($json->items as $item){
      print_r($item);
   }
}

Upvotes: 8

sujivasagam
sujivasagam

Reputation: 1769

You can use the file get content to get the full page content of the google and you can display the result in your site like

function file_get_contents_curl($url) {
    $ch = curl_init();

    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); //Set curl to return the data instead of printing it to the browser.
    curl_setopt($ch, CURLOPT_URL, $url);

    $data = curl_exec($ch);
    curl_close($ch);

    return $data;
}

$query = "search term";
$url = 'http://www.google.co.in/search?q='.urlencode($query).'';
$scrape = file_get_contents_curl($url);

Upvotes: 4

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