CODEWITHSUNDEEP
javajunitxunit
sdicola
sdicola

Reputation: 962

Junit - Compare that two XML documents are identical

I have two XML files and I am comparing them using XUnit using the following test:

@Test
public void testSortXML() throws IOException
{
    field = "userid";
    outputStream = new ByteArrayOutputStream();
    xmlStreamSorter.sort(inputStream, outputStream, comparator);
    ByteArrayInputStream expected = new ByteArrayInputStream("<?xml version=\"1.0\" encoding=\"UTF-8\"?> <users><user><userid>10</userid></user><user><userid>3</userid></user><user><userid>1</userid></user></users>"
            .getBytes());

    System.out.println(outputStream);
    Assert.assertThat(expected, CompareMatcher.isIdenticalTo(outputStream));

}

But the test fails with the following error:

Expected child nodelist length '3' but was '0' - comparing <users...> at /users[1] to <byteArrayOutputStream...> at /byteArrayOutputStream[1] (DIFFERENT)

This is the content of the output variable: 

<?xml version="1.0" encoding="UTF-8"?>
<users>
  <user>
    <userid>10</userid>
  </user>
  <user>
    <userid>3</userid>
  </user>
  <user>
    <userid>1</userid>
  </user>
</users>

They are identical. How come the test fails?

Upvotes: 2

Views: 2349

Answers (1)

sdicola
sdicola

Reputation: 962

The problem was that I did not ignored the whitespace. To do it with XUnit 2.x just create a custom Diff this way:

Diff xmlDiff = DiffBuilder.compare(expected)
    .withTest(outputStream.toString())
    .ignoreComments()
    .ignoreWhitespace()
    .build();

And then you can do this:

Assert.assertFalse(
    "The resulting XML is not correctly sorted",
    xmlDiff.hasDifferences()
);

Upvotes: 4

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