CODEWITHSUNDEEP
phparrays
simplepickup
simplepickup

Reputation: 15

PHP for loop order

I want to ask pretty simple question (for most of you) but I can't find the solution right now.

We have $names = array('Alex','James','Jack');

I want to use for loop to echo this:

1. Alex
2. James
3. Jack

But I'm using this loop right now which isn't working as I want it to:

for($i = 0; $i <= count($names); $i++) { echo $i.$names[$i]."<br/>"; }

and it's echoing this:

0. Alex
1. James
2. Jack

The problem is because we are starting from 0 because it's an array. If I put a starting point 1 it's missing the first object from the array.

What's the fix for that?

Upvotes: 1

Views: 464

Answers (1)

wogsland
wogsland

Reputation: 9518

Why not just increment your variable

$names = array('Alex','James','Jack');
for($i = 0; $i <= count($names); $i++) { 
    $j = $i+1;
    echo $j.$names[$i]."<br/>"; 
}

Upvotes: 3

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