CODEWITHSUNDEEP
javascriptregex
Danwen Huang
Danwen Huang

Reputation: 81

Regex - Match words that contain 2 or more 2 letter sequences of vowels

I would like to know how to match words (using javascript version of regex) that contain 2 or more 2 letter sequences of vowels (e.g. visionproof, steamier, preequip).

I'm learning regex at the moments and this is what I have so far (which only matches words containing 2 letter sequence of vowels) and also where I'm stuck at:

enter image description here

Upvotes: 3

Views: 4218

Answers (4)

Saurabh
Saurabh

Reputation: 7833

Below regex can be used for getting 2 or more sequences of 2 consecutive vowels

(\w*[aeiou]{2}\w*){2,}

{2} for 2 consecutive vowels and {2,} for 2 or more sequences

Upvotes: 0

Andy
Andy

Reputation: 658

I use http://regex101.com whenever I want to test out different regular expressions. Here is one I came up with that I believe does what you're looking for.

var text = "visionproof vision proof threevowelswouldworktoo queued",
    regex = /\w*[aeiou]{2}\w*[aeiou]{2}\w*/ig;

console.log(text.match(regex));

\w matches word characters. So, this matches 0 or more word characters followed by 2 vowels, followed by 0 or more word characters, followed by 2 vowels, followed by 0 or more word characters. My example is here.

Upvotes: 4

Dekel
Dekel

Reputation: 62566

  1. You will need to group the entire word
  2. You probably want to make sure not to catch the vowels group.
  3. You want minimum of 2 letters, so you want {2,}
  4. You will need the (?:[aeiou]{2,}) part - twice, because you want to catche this more than one time


/(\w*(?:[aeiou]{2,})\w*(?:[aeiou]{2,})\w*)/g


re = /(\w*(?:[aeiou]{2,})\w*(?:[aeiou]{2,})\w*)/g
str = 'words that contains 2 or more letters sequesnces and some triiiiple visionproof, steamier, preequip'
console.log(str.match(re))

Here is a link to regex101:
https://regex101.com/r/OtsdRA/2

If you want the word sssiiiisss not to match (because you don't have two separate blocks of vowels) you should use \w+ between the two vowels blocks: /(\w*(?:[aeiou]{2})\w+(?:[aeiou]{2})\w*)/g

Upvotes: 1

vks
vks

Reputation: 67968

\b\w*[aeiou]{2}\w*[aeiou]{2}\w*\b

Try this.See demo.

https://regex101.com/r/Ph7a0P/3

Upvotes: 1

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