CODEWITHSUNDEEP
pythonqtpyqt5
titusAdam
titusAdam

Reputation: 809

Qt: script runs before button is pressed

I have created a gui that has two buttons: one that says "Open Input File:" and one that says "Run".

When someone clicks on "Open Input File:", he/she can select a file as input, and when that person then clicks on "Run", the script runScrapy is supposed to start.

The part where the buttons are set looks like this:

def retranslateUi(self, MainWindow):
    _translate = QtCore.QCoreApplication.translate
    MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow"))
    self.pushButton.setText(_translate("MainWindow", "Open Input File:"))
    self.pushButton.clicked.connect(self.showDialog)
    self.pushButton_2.setText(_translate("MainWindow", "Run"))
    self.pushButton_2.clicked.connect(self.runScrapy)
    self.label.setText(_translate("MainWindow", "Happy Scraping"))

def showDialog(self):
    fileName = QFileDialog.getOpenFileName()
    if fileName:
        global file
        file = fileName[0]
        print(file)

def runScrapy(self):
    process = CrawlerProcess()
    process.crawl(BasicSpider)
    process.start()  # the script will block here until the crawling is finished

However, instead of running "runScrapy" when pushButton_2 is clicked, "runScrapy" starts running immediately after I start this script. I don't understand why, since showDialog does only pop up after you've clicked "Open Input File:".

Q: How do I change my code so that runScrapy only runs when pushButton_2 is clicked?

Thanks in advance!

Upvotes: 2

Views: 208

Answers (1)

ariwez
ariwez

Reputation: 1313

You should start with Qt event handling.

if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
# set your window/mainwindow here
sys.exit(app.exec_())

Maybe this tutorial is also helpful: Qt GUI app with python

Upvotes: 2

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