CODEWITHSUNDEEP
regex
JUG
JUG

Reputation: 703

Regex for line beginning with a character and ending with either of the characters

I am trying to write a regex pattern that grabs string between the first occurrence of character where it begins with "/" and may end with either "/" or "//" or none. For example -

/test1/code1
/test/code1/code2
/test/code1//code2

All of above should return code1.

I tried following regex -

\/+.*?(\/|\/\/)(.*)

However, this only stops at / following test1 and returns everything. i.e. /code1//code2.

Any suggestion on how I can ensure that the look up is for beginning with / and ending with either / or // or none?

Upvotes: 0

Views: 54

Answers (1)

Toto
Toto

Reputation: 91375

This one should do the job:

/.+?/([^/]+)(?:/|$)

The result is in group 1.

Explanation:

/       : a slash
.+?     : one or more any character not greedy
/       : a slash
([^/]+) : one or more any character that is not a slash
(?:/|$) : Non capturing group either a slash or line end

Here is a perl script using this regex:

#!/usr/bin/perl
use Modern::Perl;
use Data::Dumper;

my $re = qr!/.+?/([^/]+)(?:/|$)!;
while(<DATA>) {
    chomp;
    say (/$re/ ? "OK: \$1=$1\t $_" : "KO: $_");
}

__DATA__
/test1/code1
/test/code1/code2
/test/code1//code2

Output:

OK: $1=code1     /test1/code1
OK: $1=code1     /test/code1/code2
OK: $1=code1     /test/code1//code2

Upvotes: 1

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