CODEWITHSUNDEEP
phparraysjson
Cleggy1012
Cleggy1012

Reputation: 21

PHP check if string is in array

I have an array that looks like this:

{"permissions":["1","2"]}

I'm trying to check if a given string is in the permissions array with the following function

function hasPermission($permission) {
            return in_array($permission, array_column($this->permissions, 'permissions'));
}

When calling the function giving it the string "1" it return false even though 1 is in the permissions array

Any help would be appreciated

Thanks

EDIT

Here is a var Dump of the converted array 

array(1) { 
    ["permissions"]=> 
array(2) {[0]=> string(1) "1" 
          [1]=> string(1) "2" 
        } 
}

Upvotes: 0

Views: 399

Answers (3)

Hikmat Sijapati
Hikmat Sijapati

Reputation: 7004

Try like this...

<?php
$json = '{"permissions":["1","2"]}';
$arr = json_decode($json,true);
print_r($arr);
echo in_array(1,$arr['permissions']); // returns 1 if exists
?>

So your function must be like this....

function hasPermission($permission) {
            return in_array($permission, $this->permissions['permissions']);
}

Upvotes: 1

Jigar Patel
Jigar Patel

Reputation: 207

Try this this will work.

$permission = json_decode('{"permissions":["1","2"]}',true);
echo "<pre>";print_r($permission);
if(is_array($permission)){
 echo "this is an array";
}else{
  echo "Not an array";
}

Thanks

Upvotes: 0

John Joseph
John Joseph

Reputation: 951

array_column doesn't support 1D arrays, it returns an empty array if so.

Your $permissions array is 1D, so just use $this->permissions['permission'] to access it.

return in_array($permission, $this->permissions['permissions']);

Example:

$array =  ['permissions' => ['1', '2']];
echo (int)in_array('1', array_column($array, 'permissions')); // 0
echo (int)in_array('1', $array['permissions']); // 1

Upvotes: 0

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