CODEWITHSUNDEEP
pythonflask-restful
Kumar Swapnil
Kumar Swapnil

Reputation: 73

flask-restful : The requested URL was not found on the server

I am trying to follow the documentation of flask-restful and tried to run the following code.

from flask import Flask, request
from flask_restful import Resource, Api

app = Flask(__name__)
api = Api(app)

todos = {}

class TodoSimple(Resource):
    def get(self, todo_id):
        return {todo_id: todos[todo_id]}

    def put(self, todo_id):
        todos[todo_id] = request.form['data']
        return {todo_id: todos[todo_id]}

api.add_resource(TodoSimple, '/<string:todo_id>')

if __name__ == '__main__':
    app.run(debug=True)

But when I tried to run it with "http://127.0.0.1:5000/todo1" URL it responds with the message "The requested URL was not found on the server. If you entered the URL manually please check your spelling and try again.". What am I doing wrong with the code. Please help.

Upvotes: 3

Views: 5817

Answers (1)

mic4ael
mic4ael

Reputation: 8320

The problem is in the way you defined the url route for your resource. Right now you are trying to access it via http://127.0.0.1:5000/todo1 but you have defined TodoSimple to serve requests sent to http://127.0.0.1:5000/1. I would recommend to change the code to sth like below

api.add_resource(TodoSimple, '/todo/<int:todo_id>')

and then, try to access it via GET http://127.0.0.1:5000/todo/1

Upvotes: 5

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