Reputation: 31
I have an array in an old objective-C app that I am using to learn more "complicated" coding. It is back from the old days of OS X and was very much broken. I have gotten it to work (mostly)! However, the app has an NSMutableArray of images, 7 in total. I use a random number generator to insert the images on the screen, some code to allow them to fall, and then, using screen bounds, when they reach "0" on the Y axis they are removed from the array. I initially just had:
if( currentFrame.origin.y+currentFrame.size.height <= 0 )
{
[flakesArray removeObject:myItem];
I have read when removing objects from an array it is best practice to iterate in reverse...so I have this bit of code:
for (NSInteger i = myArray.count - 1; i >= 0; i--)
{ //added for for statement
if( currentFrame.origin.y+currentFrame.size.height <= 0 )
{
[myArray removeObjectAtIndex:i];
}
Sadly both methods result in the same mutated while enumerated error. Am I missing something obvious? If I add an NSLog statement I can get, I think, the index of the item that needs to be removed:
NSLog (@"Shazam! %ld", (long)i);
2017-01-07 14:39:42.086667 MyApp[45995:7500033] Shazam! 2
I have looked through a lot and tried several different methods including this one, which looks to be the most popular with the same error.
Thank you in advance! I will happily provide any additional information!
Adding more: Sorry guys I am not explicitly calling NSFastEnumeration but I have this:
- (void) drawRectCocoa:(NSRect)rect
{
NSEnumerator* flakesEnum = [flakesArray objectEnumerator];
then
for( i = 0; i < numberToCreate; i++ )
{
[self newObject:self];
}
while( oneFlake = [flakesEnum nextObject] )
It is here where:
if( currentFrame.origin.y+currentFrame.size.height <= 0 )
{
NSLog (@"Shazam! %i", oneFlake);
[flakesArray removeObject:oneFlake];
}
Thank you all. I am learning a lot from this discussion!
Upvotes: 0
Views: 1504
Reputation: 29764
As per the error, you may not mutate any NSMutableArray
(or any NSMutable...
collection) while it is being enumerated as part of any fast enumeration loop (for (... in ...) { ... }
).
@danh's answer works as well, but involves allocating a new array of elements. There are two simpler and more efficient ways to filter an array:
[array filterUsingPredicate:[NSPredicate predicateWithBlock:^(id element, NSDictionary<NSString *,id> *bindings) {
// if element should stay, return YES; if it should be removed, return NO
}];
or
NSMutableIndexSet *indicesToRemove = [NSMutableIndexSet new];
for (NSUInteger i = 0; i < array.count; i += 1) {
if (/* array[i] should be removed */) {
[indicesToRemove addIndex:i];
}
}
[array removeObjectsAtIndexes:indicesToRemove];
filterUsingPredicate:
will likely be slightly faster (since it uses fast enumeration itself), but depending on the specific application, removeObjectsAtIndexes:
may be more flexible.
No matter what, if you're using your array inside a fast enumeration loop, you will have to perform the modification outside of the loop. You can use filterUsingPredicate:
to replace the loop altogether, or you can keep the loop and keep track of the indices of the elements you want to remove for later.
Upvotes: 3
Reputation: 62686
There are two ways to go: (1) collect the objects to remove then remove them with removeObjectsInArray:.
NSMutableArray *removeThese = [NSMutableArray array];
for (id item in myArray) {
if (/* item satisfies some condition for removal */) {
[removeThese addObject:item];
}
}
// the following (and any other method that mutates the array) must be done
// *outside of* the loop that enumerates the array
[myArray removeObjectsInArray:removeThese];
Alternatively, reverseObjectEnumeration
is tolerant of removes during iteration...
for (id item in [myArray reverseObjectEnumerator]) {
if (/* item satisfies some condition for removal */) {
[myArray removeObject: item];
}
}
Upvotes: 3